Calculate the concentration (M)of sodium ions in a solution made by diluting 60.0 mL of a 0.374 M solution of sodium sulfide to a total volume of 350 mL.
A) 0.128
B) 0.0640
C) 0.0320
D) 0.70
E) 2.00

Question

Quizplus · Accepted Answer

The initial moles of sodium sulfide are 0.374 M * 0.060 L = 0.02244 moles. Sodium sulfide (Na2S) dissociates into 2 Na+ ions, so moles of Na+ = 2 * 0.02244 = 0.04488 moles. The final concentration of Na+ is 0.04488 moles / 0.350 L = 0.128 M.

Calculate the Concentration (M)of Sodium Ions in a Solution Made