Determine the total volume of all gases (at STP)formed when 50.0 mL of TNT (C₃H₅(NO₃)₃,d = 1.60 g/mL,molar mass = 227.10 g/mol)reacts according to the following reaction. 4 C₃H₅(NO₃)₃(l)→ 6 N₂(g)+ O₂(g)+ 12 CO₂(g)+ 10 H₂O(g) A) 4.93 L B) 57.2 L C) 29.6 L D) 448 L E) 175 L

Question

Quizplus · Accepted Answer

First, calculate the mass of TNT: $50.0 \, \text{mL} \times 1.60 \, \text{g/mL} = 80.0 \, \text{g}$. Then, find the moles of TNT: $80.0 \, \text{g} / 227.10 \, \text{g/mol} = 0.352 \, \text{mol}$. According to the balanced chemical equation, 4 moles of TNT produce a total of $6 + 7 + 12 + 10 = 35$ moles of gas. Therefore, $0.352 \, \text{mol} \, \text{TNT} \times (35 \, \text{moles gas} / 4 \, \text{moles TNT}) = 3.08 \, \text{moles gas}$. At STP, 1 mole of gas occupies 22.4 L, so $3.08 \, \text{moles} \times 22.4 \, \text{L/mol} = 69.0 \, \text{L}$.

Determine the Total Volume of All Gases (At STP)formed When