A 6.50-g sample of liquid water at 25.0 C is heated by the addition of 145 J of energy.The final temperature of the water is ________°C.The specific heat capacity of liquid water is
A) 118
B) 25.2
C) -19.7
D) 30.3
E) 5.34

Question

A 6.50-g sample of liquid water at 25.0 C is heated by the addition of 145 J of energy.The final temperature of the water is ________°C.The specific heat capacity of liquid water is 
A) 118 
B) 25.2 
C) -19.7 
D) 30.3 
E) 5.34

Quizplus · Accepted Answer

We can use the formula:

q = mCΔT

where q is the amount of energy added, m is the mass of the water, C is the specific heat capacity of water, and ΔT is the change in temperature.

We can rearrange this formula to solve for the final temperature:

ΔT = q / (mC)

ΔT = 145 J / (6.50 g * 4.18 J/g°C)

ΔT = 5.34°C

Then, we can add this change in temperature to the initial temperature of 25.0°C to find the final temperature:

Tfinal = 25.0°C + 5.34°C

Tfinal = 30.3°C

Therefore, the answer is D) 30.3°C.

A 650-G Sample of Liquid Water at 25