Given the following rate law,how does the rate of reaction change if the concentration of Y is doubled? Rate = k[X]4[Y]3
A) The rate of reaction will increase by a factor of 6.
B) The rate of reaction will decrease by a factor of 4.
C) The rate of reaction will increase by a factor of 8.
D) The rate of reaction will increase by a factor of 4.
E) The rate of reaction will remain unchanged.
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