The rate of disappearance of HBr in the gas phase reaction 2HBr (g) → H₂ (g) + Br₂ (g)
Is 0.301 Ms^-1 at 150°C. The rate of appearance of Br₂ is __________ Ms^-1.

Question

The rate of disappearance of HBr in the gas phase reaction 2HBr (g)→ H₂ (g)+ Br₂ (g) Is 0.301 Ms^-1 at 150°C. The rate of appearance of Br₂ is __________ Ms^-1.

Quizplus · Accepted Answer

The rate of appearance of Br₂ is half the rate of disappearance of HBr because the stoichiometry of the reaction shows that 2 moles of HBr produce 1 mole of Br₂. Therefore, the rate is 0.301 Ms⁻¹ / 2 = 0.1505 Ms⁻¹, which is approximately 0.151 Ms⁻¹.

The Rate of Disappearance of HBr in the Gas Phase