At elevated temperatures, methylisonitrile (CH₃NC) isomerizes to acetonitrile (CH₃CN) : CH₃NC (g) → CH₃CN (g)
At the start of an experiment, there are 0.200 mol of reactant and 0 mol of product in the reaction vessel. After 25 min, 0.106 mol of reactant (CH₃NC) remain. There are __________ mol of product (CH₃CN) in the reaction vessel.

Question

Quizplus · Accepted Answer

To solve this problem, we can use the balanced chemical equation and the given information to calculate the amount of product produced. First, we need to calculate the moles of reactant that reacted in 25 minutes: 0.200 mol - 0.106 mol = 0.094 mol This means that 0.094 mol of CH₃NC was converted to CH₃CN. Since the reaction is 1:1, this also means that 0.094 mol of CH₃CN was produced. Therefore, the answer is E) 0.094.

At Elevated Temperatures, Methylisonitrile (CH3NC)isomerizes to Acetonitrile (CH3CN): CH3NC (G)→

At Elevated Temperatures, Methylisonitrile (CH₃NC)isomerizes to Acetonitrile (CH₃CN): CH₃NC (G)→