Consider the following reaction at equilibrium.What effect will increasing the pressure of the reaction mixture have on the system? CuS(s)+ O₂(g)⇌ Cu(s)+ SO₂(g)

Question

Quizplus · Accepted Answer

Increasing the pressure of a reaction mixture affects the equilibrium position only if there are different numbers of moles of gases on each side of the equation. In this case, both sides of the equation have the same number of gas moles (one mole of gas on each side), so changing the pressure will have no effect on the equilibrium position. The equilibrium constant remains unchanged with pressure.

Consider the Following Reaction at Equilibrium