Consider the following reaction at equilibrium.What effect will reducing the pressure have on the system? C₃H₈(g)+ 5 O₂(g)⇌ 3 CO₂(g)+ 4 H₂O(l)ΔH° = -2220 kJ

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Reducing the pressure in a system at equilibrium favors the side with more moles of gas. In this reaction, the left side has 6 moles of gas (1 mole of CS + 5 moles of O) and the right side has 3 moles of gas (3 moles of CO). Therefore, reducing the pressure will shift the equilibrium to the left, towards the reactants.

Consider the Following Reaction at Equilibrium