The K_p for the reaction below is 1.49 × 10⁸ at 100.0°C: CO(g) + (g) ⇌ (g)
In an equilibrium mixture of the three gases, = = 2.22 × 10^-4 atm.The partial pressure of the product,phosgene ( ) ,is ________ atm.

Question

The K_p for the reaction below is 1.49 × 10⁸ at 100.0°C: CO(g) + The Kp for the reaction below is 1.49 × 108 at 100.0°C: CO(g) + (g) ⇌ (g) In an equilibrium mixture of the three gases, = = 2.22 × 10-4 atm.The partial pressure of the product,phosgene ( ) ,is ________ atm. A) 7.34 B) 3.02 × 1015 C) 3.31 × 10-16 D) 3.31 × 104 E) 6.67 × 1011

The K<sub>p</sub> for the reaction below is 1.49 × 10<sup>8</sup> at 100.0°C: CO(g) + (g) ⇌ (g) In an equilibrium mixture of the three gases, = = 2.22 × 10<sup>-4</sup> atm.The partial pressure of the product,phosgene ( ) ,is ________ atm. A) 7.34 B) 3.02 × 10<sup>15</sup> C) 3.31 × 10<sup>-16</sup> D) 3.31 × 10<sup>4</sup> E) 6.67 × 10<sup>11</sup>

(g) ⇌

(g)
In an equilibrium mixture of the three gases, The Kp for the reaction below is 1.49 × 108 at 100.0°C: CO(g) + (g) ⇌ (g) In an equilibrium mixture of the three gases, = = 2.22 × 10-4 atm.The partial pressure of the product,phosgene ( ) ,is ________ atm. A) 7.34 B) 3.02 × 1015 C) 3.31 × 10-16 D) 3.31 × 104 E) 6.67 × 1011

=

= 2.22 × 10^-4 atm.The partial pressure of the product,phosgene ( The Kp for the reaction below is 1.49 × 108 at 100.0°C: CO(g) + (g) ⇌ (g) In an equilibrium mixture of the three gases, = = 2.22 × 10-4 atm.The partial pressure of the product,phosgene ( ) ,is ________ atm. A) 7.34 B) 3.02 × 1015 C) 3.31 × 10-16 D) 3.31 × 104 E) 6.67 × 1011

) ,is ________ atm.

Quizplus · Accepted Answer

The Answer of The K_p for the reaction below is 1.49 × 10⁸ at 100.0°C: CO(g)+ (g)⇌ (g) In an equilibrium mixture of the three gases, = = 2.22 × 10^-4 atm.The partial pressure of the product,phosgene ( ),is ________ atm.

The Kp for the Reaction Below Is 1

The K_p for the Reaction Below Is 1