The equilibrium constant is given for one of the reactions below.Determine the value of the missing equilibrium constant. 2 HD(g) ⇌ H₂(g) + D₂(g) K_c = 0.28
5 H₂(g) + 5 D₂(g) ⇌ 10 HD(g) K_c = ?

Question

The equilibrium constant is given for one of the reactions below.Determine the value of the missing equilibrium constant. 2 HD(g)⇌ H₂(g)+ D₂(g)K_c = 0.28 5 H₂(g)+ 5 D₂(g)⇌ 10 HD(g)K_c = ?

Quizplus · Accepted Answer

The equilibrium constant for the first reaction is given as K = 0.28. We can use this value to find the equilibrium constant for the second reaction using the following relationship:

K2 = (K1)n

where n is the stoichiometric coefficient of the balanced equation for the second reaction. In this case, n = 10 (since there are 10 moles of HD on the product side and 5 moles each of HS and DS on the reactant side).

Thus, we have:

K2 = (0.28)^10 = 581

Therefore, the missing equilibrium constant is 581, which corresponds to choice D.

The Equilibrium Constant Is Given for One of the Reactions