A voltaic cell is constructed with two Zn²⁺-Zn electrodes,where the half-reaction is Zn²⁺ + 2e^- → Zn(s) E° = -0.763 V
The concentrations of zinc ion in the two compartments are 5.50 M and 1.11 × 10^-2 M,respectively.The cell emf is ________ V.

Question

Quizplus · Accepted Answer

The cell emf can be calculated using the Nernst equation. Since both electrodes are the same, the standard cell potential is 0 V. The Nernst equation is E = E° - (RT/nF) * ln(Q), where Q is the reaction quotient. For this cell, E = 0 - (0.0257/2) * ln(1.11 × 10^-2 / 5.50), which calculates to approximately 0.0798 V.

A Voltaic Cell Is Constructed with Two Zn2+-Zn Electrodes,where the Half-Reaction

A Voltaic Cell Is Constructed with Two Zn²⁺-Zn Electrodes,where the Half-Reaction