Consider the class Class Value { Private T v; Public Value(T v1){ V = v1; } Public void output(){ System.out.println(v); } } The code Value nV = new Value(12); A) will cause a compiler error B) will compile correctly,but cause an exception at run time C) will compile and run correctly D) None of the above

Question

Consider the class Class Value < T extends Number > { Private T v; Public Value(T v1){ V = v1; } Public void output(){ System.out.println(v); } } The code Value< Number > nV = new Value< Number >(12); A) will cause a compiler error B) will compile correctly,but cause an exception at run time C) will compile and run correctly D) None of the above

Quizplus · Accepted Answer

The code will compile and run correctly because the generic class Value has a type parameter bounded by Number, which means it can accept any type of Number, including Integer, Double, Float, etc. and will print out the value of the input. Therefore, the statement Value nV = new Value(12) will create a new instance of Value with an Integer value of 12 and assign it to nV, which is of type Value. The output() method will print out 12 with no errors.

Consider the Class Class Value < T Extends Number >