What is the molarity of an NaI solution that contains 5.3 g of NaI in 41.0 mL of solution?

Question

Quizplus · Accepted Answer

First, we need to convert the given mass of NaI into moles:

moles NaI = 5.3 g / 149.89 g/mol = 0.0354 mol

Next, we need to convert the given volume of solution into liters:

41.0 mL = 0.0410 L

Finally, we can calculate the molarity (M) of the solution:

M = moles / liters

M = 0.0354 mol / 0.0410 L

M = 0.8598 M, which rounds to 0.86 M. Therefore, the answer is choice A.

What Is the Molarity of an NaI Solution That Contains