How much energy is needed to convert 57.5 grams of ice at 0.00°C to liquid water at 75.0°C?
Specific heat capacity (ice)= 2.10 J/g°C
Specific heat capacity (liquid water)= 4.18 J/g°C
Heat of fusion = 333 J/g
Heat of vaporization = 2258 J/g

Question

Quizplus · Accepted Answer

First, calculate the energy to melt the ice: 57.5 g * 333 J/g = 19147.5 J. Then, calculate the energy to heat the water from 0°C to 75°C: 57.5 g * 4.18 J/g°C * 75°C = 17992.5 J. Total energy = 19147.5 J + 17992.5 J = 37140 J = 37.14 kJ, which rounds to 37.2 kJ.

How Much Energy Is Needed to Convert 57