Solved

The Standard Enthalpy Change for the Combustion of 1 Mole \to

Question 64

Multiple Choice

The standard enthalpy change for the combustion of 1 mole of propane is -2043.0 kJ.C3H8(g) + 5 O2(g) \to 3 CO2(g) + 4 H2O(g)
Calculate Δ\Delta fH \circ for propane based on the following standard molar enthalpies of formation. The standard enthalpy change for the combustion of 1 mole of propane is -2043.0 kJ.C<sub>3</sub>H<sub>8</sub>(g) + 5 O<sub>2</sub>(g)  \to  3 CO<sub>2</sub>(g) + 4 H<sub>2</sub>O(g)  Calculate  \Delta <sub>f</sub>H<sup> \circ </sup> for propane based on the following standard molar enthalpies of formation.  A)  -1407.7 kJ/mol-rxn B)  +104.7 kJ/mol-rxn C)  -104.7 kJ/mol-rxn D)  -4190.7 kJ/mol-rxn E)  +1407.7 kJ/mol-rxn


A) -1407.7 kJ/mol-rxn
B) +104.7 kJ/mol-rxn
C) -104.7 kJ/mol-rxn
D) -4190.7 kJ/mol-rxn
E) +1407.7 kJ/mol-rxn

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions

Unlock this Answer For Free Now!

View this answer and more for free by performing one of the following actions

qr-code

Scan the QR code to install the App and get 2 free unlocks

upload documents

Unlock quizzes for free by uploading documents