Ammonia gas is synthesized according to the balanced equation below.
N₂(g) + 3 H₂(g) $\to$ 2 NH₃(g)
If 1.55 L N₂ react with 4.92 L H₂,what is the theoretical yield (in liters) of NH₃? Assume that the volumes of reactants and products are measured at the same temperature and pressure.

Question

Ammonia gas is synthesized according to the balanced equation below.
N₂(g) + 3 H₂(g)

\to

2 NH₃(g)
If 1.55 L N₂ react with 4.92 L H₂,what is the theoretical yield (in liters) of NH₃? Assume that the volumes of reactants and products are measured at the same temperature and pressure.

Quizplus · Accepted Answer

The limiting reactant is N2, which produces 2 moles of NH3 for every 1 mole of N2. Therefore, 1.55 L of N2 will produce 2 * 1.55 L = 3.10 L of NH3.

Ammonia Gas Is Synthesized According to the Balanced Equation Below →\to→

Ammonia Gas Is Synthesized According to the Balanced Equation Below $\to$