Niobium crystallizes in a body-centered cubic lattice.If the radius of niobium is 146 pm,what is the unit cell edge length?

Question

Quizplus · Accepted Answer

In a body-centered cubic (BCC) lattice, the relationship between the atomic radius (r) and the unit cell edge length (a) is given by the formula: a = 4r/√3. Substituting the given radius of niobium (146 pm) into this formula gives a = 4(146 pm)/√3 ≈ 337 pm.

Niobium Crystallizes in a Body-Centered Cubic Lattice