What is the freezing point of a 0.24 m solution of glucose,C₆H₁₂O₆,in water? (K_fp for water is 1.858°C/m.) A) 0.22°C B) 0.45°C C) -0.45°C D) -0.22°C E) -0.89°C

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The freezing point depression can be calculated using the formula ΔTf = i * Kfp * m, where i is the van't Hoff factor (1 for glucose), Kfp is the freezing point depression constant, and m is the molality. ΔTf = 1 * 1.858°C/m * 0.24 m = 0.44592°C. The freezing point of pure water is 0°C, so the solution's freezing point is 0°C - 0.44592°C ≈ -0.45°C.

What Is the Freezing Point of a 0