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For Which of the Following Equilibria Does K_c = K_p

Question 13

Question 13

Multiple Choice

For which of the following equilibria does K_c = K_p?

A) N₂(g) + 3H₂(g) For which of the following equilibria does K<sub>c</sub> = K<sub>p</sub>? A) N<sub>2</sub>(g) + 3H<sub>2</sub>(g) 2NH<sub>3</sub>(g) B) CO(g) + H<sub>2</sub>O(g) CO<sub>2</sub>(g) + H<sub>2</sub>(g) C) CO(g) + 3H<sub>2</sub>(g) CH<sub>4</sub>(g) + H<sub>2</sub>O(g) D) CaO(s) + CO<sub>2</sub>(g) CaCO<sub>3</sub>(s) E) HBr(g) ½H<sub>2</sub>(g) + ½Br<sub>2</sub>(l) 2NH₃(g)
B) CO(g) + H₂O(g) For which of the following equilibria does K<sub>c</sub> = K<sub>p</sub>? A) N<sub>2</sub>(g) + 3H<sub>2</sub>(g) 2NH<sub>3</sub>(g) B) CO(g) + H<sub>2</sub>O(g) CO<sub>2</sub>(g) + H<sub>2</sub>(g) C) CO(g) + 3H<sub>2</sub>(g) CH<sub>4</sub>(g) + H<sub>2</sub>O(g) D) CaO(s) + CO<sub>2</sub>(g) CaCO<sub>3</sub>(s) E) HBr(g) ½H<sub>2</sub>(g) + ½Br<sub>2</sub>(l) CO₂(g) + H₂(g)
C) CO(g) + 3H₂(g) For which of the following equilibria does K<sub>c</sub> = K<sub>p</sub>? A) N<sub>2</sub>(g) + 3H<sub>2</sub>(g) 2NH<sub>3</sub>(g) B) CO(g) + H<sub>2</sub>O(g) CO<sub>2</sub>(g) + H<sub>2</sub>(g) C) CO(g) + 3H<sub>2</sub>(g) CH<sub>4</sub>(g) + H<sub>2</sub>O(g) D) CaO(s) + CO<sub>2</sub>(g) CaCO<sub>3</sub>(s) E) HBr(g) ½H<sub>2</sub>(g) + ½Br<sub>2</sub>(l) CH₄(g) + H₂O(g)
D) CaO(s) + CO₂(g) For which of the following equilibria does K<sub>c</sub> = K<sub>p</sub>? A) N<sub>2</sub>(g) + 3H<sub>2</sub>(g) 2NH<sub>3</sub>(g) B) CO(g) + H<sub>2</sub>O(g) CO<sub>2</sub>(g) + H<sub>2</sub>(g) C) CO(g) + 3H<sub>2</sub>(g) CH<sub>4</sub>(g) + H<sub>2</sub>O(g) D) CaO(s) + CO<sub>2</sub>(g) CaCO<sub>3</sub>(s) E) HBr(g) ½H<sub>2</sub>(g) + ½Br<sub>2</sub>(l) CaCO₃(s)
E) HBr(g) For which of the following equilibria does K<sub>c</sub> = K<sub>p</sub>? A) N<sub>2</sub>(g) + 3H<sub>2</sub>(g) 2NH<sub>3</sub>(g) B) CO(g) + H<sub>2</sub>O(g) CO<sub>2</sub>(g) + H<sub>2</sub>(g) C) CO(g) + 3H<sub>2</sub>(g) CH<sub>4</sub>(g) + H<sub>2</sub>O(g) D) CaO(s) + CO<sub>2</sub>(g) CaCO<sub>3</sub>(s) E) HBr(g) ½H<sub>2</sub>(g) + ½Br<sub>2</sub>(l) ½H₂(g) + ½Br₂(l)

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