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The Equilibrium Constant at 25 \circ C for the Dissolution of Silver Iodide Is
8

Question 41

Multiple Choice

The equilibrium constant at 25 \circ C for the dissolution of silver iodide is
8.5 ×\times 10-17.AgI(s)  The equilibrium constant at 25 <sup> \circ </sup>C for the dissolution of silver iodide is  8.5  \times  10<sup>-17</sup>.AgI(s)    Ag<sup>+</sup>(aq) + I<sup>-</sup>(aq)  If an excess quantity of AgI(s) is added to water and allowed to equilibrate,what is the equilibrium concentration of I<sup>-</sup>? A)  7.2  \times  10<sup>-33</sup> M B)  4.3  \times  10<sup>-17</sup> M C)  8.5  \times  10<sup>-17</sup> M D)  6.5  \times  10<sup>-9</sup> M E)  9.2  \times  10<sup>-9</sup> M Ag+(aq) + I-(aq)
If an excess quantity of AgI(s) is added to water and allowed to equilibrate,what is the equilibrium concentration of I-?


A) 7.2 ×\times 10-33 M
B) 4.3 ×\times 10-17 M
C) 8.5 ×\times 10-17 M
D) 6.5 ×\times 10-9 M
E) 9.2 ×\times 10-9 M

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