What is the value of the dissociation constant,K_d,for the complex ion Cd(NH₃)₄²⁺? For Cd(NH₃)₄²⁺,K_f = 1.0 $\times$ 10⁷. A) 1.0 $\times$ 10^-7 B) 2.5 $\times$ 10⁶ C) 1.0 $\times$ 10⁷ D) 5.6 $\times$ 10¹ E) 1.0 $\times$ 10^-7

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Quizplus · Accepted Answer

K_d = 1/K_f = 1/1.0 F1F1F1S1F1F1F10 10⁷ = 1.0 F1F1F1S1F1F1F10 10^-7

What Is the Value of the Dissociation Constant,Kd,for the Complex ×\times×

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