A 25.0 mL sample of 0.10 M sodium benzoate is titrated with 0.10 M HCl(aq).What is the pH after the addition of 32.0 mL of HCl(aq)? (K_b of C₆H₅CO₂^- = 1.6 $\times$ 10^-10) A) 1.00 B) 1.25 C) 1.91 D) 4.20 E) 9.79

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After adding 32.0 mL of 0.10 M HCl to 25.0 mL of 0.10 M sodium benzoate, the solution contains excess HCl, making it acidic. The pH is determined by the concentration of the excess HCl, which is 0.032 M, leading to a pH of approximately 1.91.

A 250 ML Sample of 0 ×\times× 10-10) A) 1

A 250 ML Sample of 0 $\times$ 10^-10)
A) 1