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What Is the Equilibrium Constant for the Reaction Below at 25

Question 72

Multiple Choice

What is the equilibrium constant for the reaction below at 25 \circ C? (R = 8.314 J/K.mol)

MgCO3(s)  What is the equilibrium constant for the reaction below at 25 <sup> \circ </sup>C? (R = 8.314 J/K.mol)   MgCO<sub>3</sub>(s)    MgO(s) + CO<sub>2</sub>(g)   Given  \Delta <sub>f</sub>G<sup> \circ </sup>[MgCO<sub>3</sub>(s) ] = -1028.2 kJ/mol, \Delta <sub>f</sub>G [MgO(s) ] = -568.8 kJ/mol,and  \Delta <sub>f</sub>G<sup> \circ </sup> [CO<sub>2</sub>(g) ] = -394.4 kJ/mol. A)  4.0  \times  10<sup>-12</sup> B)  0.97 C)  1.0 D)  1.0  \times  10<sup>4</sup> E)  2.5  \times  10<sup>11</sup> MgO(s) + CO2(g)

Given Δ\Delta fG \circ [MgCO3(s) ] = -1028.2 kJ/mol, Δ\Delta fG [MgO(s) ] = -568.8 kJ/mol,and Δ\Delta fG \circ [CO2(g) ] = -394.4 kJ/mol.


A) 4.0 ×\times 10-12
B) 0.97
C) 1.0
D) 1.0 ×\times 104
E) 2.5 ×\times 1011

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