What is the nuclear binding energy per nucleon of a nucleus? (c = 3.00 $\times$ 10⁸ m/s,1 amu = 1.66054 $\times$ 10^-27 kg)

Question

Quizplus · Accepted Answer

The nuclear binding energy per nucleon can be calculated using the formula:
BE/A = [Z(mp) + N(mn) - M]/A

where BE is the binding energy, Z is the atomic number, mp is the mass of proton, N is the number of neutrons, mn is the mass of neutron, M is the mass of the nucleus, and A is the mass number.

Using the given values, we can calculate the binding energy as:
BE = [23(1.00728 u) + 44(1.00867 u) - 65.926036 u]c^2
BE = 969.6 MeV

The number of nucleons is A = 23 + 44 = 67, so the binding energy per nucleon is:
BE/A = 969.6 MeV / 67 = 14.46 MeV/nucleon

Converting MeV to J, we get:
14.46 MeV/nucleon x (1.60218 x 10^-13 J/MeV) = 2.318 x 10^-12 J/nucleon

Therefore, the best choice is C, which is 11ea8937_abb8_4c63_a16d_215eec90a450_TB4499_00 J/nucleon.

What Is the Nuclear Binding Energy Per Nucleon of a ×\times×

What Is the Nuclear Binding Energy Per Nucleon of a $\times$