Calculate q when 28.6 g of water is heated from 22.0°C to 78.3°C.

Name: Calculate q when 28.6 g of water is heated from 22.0°C to 78.3°C.
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Question

Quizplus · Accepted Answer

q = mcΔT, where m is the mass of water, c is the specific heat capacity of water, and ΔT is the change in temperature. 
m = 28.6 g 
c = 4.184 J/g°C (specific heat capacity of water) 
ΔT = (78.3°C - 22.0°C) = 56.3°C 
q = (28.6 g)(4.184 J/g°C)(56.3°C) = 6.74 kJ. 
Therefore, the answer is C.

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