The rate constant for the reaction 3A $\rightarrow$ 4B is 6.00 *10¯³ L mol¯¹min¯¹. How long will it take the concentration of A to drop from 0.75 M to 0.25 M?

Question

Quizplus · Accepted Answer

The reaction is a second-order reaction (since the units of the rate constant are L mol¯¹ min¯¹). For a second-order reaction, the time taken can be calculated using the formula: t = (1/k) * ((1/[A]₀) - (1/[A])). Substituting the given values, t = (1/6.00 * 10¯³) * ((1/0.25) - (1/0.75)) = 440 min.

The Rate Constant for the Reaction 3A →\rightarrow→ 4B Is 600 *10¯3 L Mol¯1min¯1

The Rate Constant for the Reaction 3A $\rightarrow$ 4B Is 600 *10¯³ L Mol¯¹min¯¹