What is the theoretical yield in grams of CuS for the following reaction given that you start with 15.5 g of Na₂S and 12.1 g CuSO₄?
Reaction: Na₂S + CuSO₄→ Na₂SO₄ + CuS

Question

What is the theoretical yield in grams of CuS for the following reaction given that you start with 15.5 g of Na₂S and 12.1 g CuSO₄? Reaction: Na₂S + CuSO₄→ Na₂SO₄ + CuS

Quizplus · Accepted Answer

To find the theoretical yield of CuS, first determine the limiting reactant. Calculate moles of Na2S (15.5 g / 78.05 g/mol = 0.198 mol) and CuSO4 (12.1 g / 159.61 g/mol = 0.0758 mol). CuSO4 is the limiting reactant. The reaction produces 1 mole of CuS per mole of CuSO4, so 0.0758 mol of CuS is formed. The mass of CuS is 0.0758 mol * 95.61 g/mol = 7.25 g.

What Is the Theoretical Yield in Grams of CuS for the Following