How many kJ of heat are needed to completely vaporize 3.30 moles of H₂O? The heat of vaporization for water at the boiling point is 40.6 kJ/mole.

Name: How many kJ of heat are needed to completely vaporize 3.30 moles of H 2 O? The heat of vaporization for water at the boiling point is 40.6 kJ/mole.
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Quizplus · Accepted Answer

To find the total heat needed to vaporize 3.30 moles of water, multiply the number of moles by the heat of vaporization: 3.30 moles * 40.6 kJ/mole = 133.98 kJ, which rounds to 134 kJ.

How Many KJ of Heat Are Needed to Completely Vaporize