Question 1

What will happen if a healthy red blood cell is placed into a container of pure water?

Accepted Answer

This is because pure water is hypotonic (has a lower concentration of solutes) compared to the cytoplasm of a red blood cell. Water will move from an area of higher concentration (the pure water) to an area of lower concentration (inside the red blood cell) resulting in the cell becoming swollen.

Question 2

What is the concentration of sodium chloride in the final solution if 25.34 mL of 0.113 M BaCl₂ completely reacts and the total volume of the reaction is 110.4 mL,given the reaction: BaCl₂ (aq)+ Na₂SO₄(aq)→ BaSO₄ (s)+ 2NaCl (aq)

Accepted Answer

First, we need to determine the number of moles of BaCl2 that reacted:
0.113 mol/L x 0.02534 L = 0.002864 mol BaCl2

Since the stoichiometry of the reaction is 1:2 for BaCl2:NaCl, we know that twice the number of moles of NaCl were produced:
2 x 0.002864 mol = 0.005728 mol NaCl

Next, we need to determine the final concentration of NaCl in the solution:
0.005728 mol / 0.1104 L = 0.0519 mol/L or 0.0519 M

Therefore, the correct choice is C, with a final concentration of 0.0519 M.

Question 3

What is the molality of a solution made by dissolving 14.7 g of C₆H₁₂O₆ into 150.0 mL of water? Assume the density of water is 1.00 g/mL.

Accepted Answer

Molality (m) is calculated as moles of solute per kilogram of solvent. The molar mass of C6H12O6 is 180.18 g/mol. Moles of C6H12O6 = 14.7 g / 180.18 g/mol = 0.0816 mol. Mass of water = 150.0 g = 0.150 kg. Molality = 0.0816 mol / 0.150 kg = 0.544 m.

Question 4

What volume of 12.0 M HCl is required to make 75.0 mL of 3.50 M HCl?

Accepted Answer

Use the formula M1V1 = M2V2
(12.0 M)(V1) = (3.50 M)(75.0 mL)
V1 = (3.50 M)(75.0 mL)/(12.0 M) = 21.9 mL.

Question 5

How many grams of barium sulfate are produced if 25.34 mL of 0.113 M BaCl₂ completely react given the reaction: BaCl₂ (aq)+ Na₂SO₄(aq)→ BaSO₄ (s)+ 2NaCl (aq)

Accepted Answer

The answer of How many grams of barium sulfate are...

Question 6

What molarity should the stock solution be if you want to dilute 25.0 mL to 2.00 L and have the final concentration be 0.103 M?

Accepted Answer

First, use the dilution equation: 
M1V1 = M2V2 
where M1 is the initial concentration (unknown), V1 is the initial volume (25.0 mL = 0.025 L), M2 is the final concentration (0.103 M), and V2 is the final volume (2.00 L). 
Rearranging the equation to solve for M1: 
M1 = (M2V2)/V1 
M1 = (0.103 M)(2.00 L)/(0.025 L) 
M1 = 8.24 M 
Therefore, the stock solution should be 8.24 M in order to dilute 25.0 mL to 2.00 L and have the final concentration be 0.103 M.

Question 7

How many milliliters of 0.755 M H₂SO₄ solution is needed to react with 55.0 mL of 2.50 M KOH solution? Given: 2 KOH (aq)+ H₂SO₄ (aq)→ 2 H₂O (l)+ K₂SO₄ (aq)

Accepted Answer

First, we need to balance the equation: 2 KOH (aq) + H₂SO₄ (aq) → 2 H₂O (l) + K₂SO₄ (aq) According to the equation, one mole of KOH reacts with one mole of H₂SO₄. To calculate how many moles of H₂SO₄ we need: moles of KOH = concentration × volume = 2.50 M × 0.0550 L = 0.1375 mol KOH From the balanced equation, we know that 2 moles of KOH reacts with 1 mole of H₂SO₄. Therefore, moles of H₂SO₄ = 0.1375 mol KOH ÷ 2 = 0.06875 mol H₂SO₄ Finally, we can use the molarity to calculate the volume of the H₂SO₄ solution: volume = moles ÷ concentration = 0.06875 mol ÷ 0.755 M = 0.0911 L = 91.1 mL Therefore, the answer is (C) 91.1 mL.

Question 8

What is the change in the freezing point of a solution made by dissolving 14.7 g of C₆H₁₂O₆ into 150.0 mL of water? The density of water is 1.00 g/mL and K_f = 1.86°C/m.

Accepted Answer

The answer of What is the change in the freezing...

Question 9

How many mL of 0.218 M sodium sulfate react with exactly 25.34 mL of 0.113 M BaCl₂ given the reaction: BaCl₂ (aq)+ Na₂SO₄(aq)→ BaSO₄ (s)+ 2NaCl (aq)

Accepted Answer

The balanced equation shows a 1:1 molar ratio between BaCl₂ and Na₂SO₄. Calculate moles of BaCl₂: 0.113 M * 0.02534 L = 0.002867 moles. Since the ratio is 1:1, moles of Na₂SO₄ needed = 0.002867. Volume of Na₂SO₄ = moles / concentration = 0.002867 / 0.218 M = 0.0131 L = 13.1 mL.

Question 10

An osmosis cell is constructed of a "U" shaped tube with a semipermeable membrane separating the two arms of the tube.Suppose a concentrated solution is placed in the left arm of the U-tube,and a dilute concentration of the same substance is poured into the other arm to the same height.After a period of time has elapsed,you would expect to find that

Accepted Answer

The answer of An osmosis cell is constructed of a...

Question 11

Osmotic pressure is:

Accepted Answer

Osmotic pressure is the pressure required to stop the flow of solvent (usually water) from a solution of lower solute concentration to a solution of higher solute concentration through a semipermeable membrane. This occurs because the solute particles cannot cross the membrane, but the solvent particles (usually water) can. This causes the higher solute concentration solution to have a lower water potential, and therefore the water flows from the lower solute concentration side to the higher solute concentration side, resulting in osmotic pressure. Therefore, the correct option is D, the pressure required to stop the flow of solvent from a region of low solute concentration through a semipermeable membrane into a region of high solute concentration.

Question 12

If you add 4.00 mL of pure water to 6.00 mL of 0.750 M NaCl solution,what is the concentration of sodium chloride in the diluted solution?

Accepted Answer

Step 1: Calculate the number of moles of NaCl in the original solution:
6.00 mL of 0.750 M NaCl solution = (6.00/1000)L x 0.750 mol/L = 0.00450 mol NaCl
Step 2: Calculate the total volume of the diluted solution:
6.00 mL + 4.00 mL = 10.00 mL = 0.01000 L
Step 3: Calculate the concentration of NaCl in the diluted solution:
0.00450 mol / 0.01000 L = 0.450 M
Therefore, the answer is B) 0.450 M.

Question 13

What is the change in the boiling point of a solution made by dissolving 14.7 g of C₆H₁₂O₆ into 150.0 mL of water? The density of water is 1.00 g/mL and K_b = 0.512°C/m.

Accepted Answer

First, we need to calculate the molality of the solution:

molality = moles of solute / mass of solvent in kg

mass of solvent = volume of water x density of water = 150.0 mL x 1.00 g/mL = 150.0 g = 0.150 kg

moles of solute = mass of solute / molar mass = 14.7 g / 152.3 g/mol = 0.0965 mol

molality = 0.0965 mol / 0.150 kg = 0.6433 mol/kg

Next, we can use the equation:

ΔTb = Kb x molality

where ΔTb is the change in boiling point, Kb is the boiling point elevation constant (given as 0.512°C/m), and molality is the molality of the solution we just calculated.

ΔTb = 0.512°C/m x 0.6433 mol/kg = 0.3296°C

Therefore, the change in boiling point is 0.279°C, which is answer choice D.

Question 14

Which of the following statements about colligative properties is FALSE?

Accepted Answer

All the statements provided are true regarding colligative properties. Colligative properties depend on the number of particles in a solution, not the identity of the solute, which is why the boiling point elevation and freezing point depression occur with the addition of a solute like salt, and these changes are indeed proportional to the molality of the solution.

Question 15

Why is NOT a good idea to drink seawater when people are lost at sea?

Accepted Answer

The high concentration of salt forces water out of the cells lining your stomach and intestine.

Question 16

In comparing a 0.25 molality aqueous NaCl solution to a 0.25 molality aqueous CaCl₂ solution,

Accepted Answer

The CaCl2 solution has a higher boiling point and a lower freezing point due to the van't Hoff factor. CaCl2 dissociates into three ions (Ca^2+ and 2 Cl^-), while NaCl dissociates into two ions (Na^+ and Cl^-), leading to a greater colligative effect for CaCl2.

Question 17

What volume of 9.00 M nitric acid is needed to make 6.50 L of 1.25 M solution?

Accepted Answer

The answer of What volume of 9.00 M nitric acid...

Question 18

Oftentimes solubility of a compound limits the concentration of the solution that can be prepared.Use the solubility data given with each compound shown below to determine which compound would allow the preparation of a 10.0 Molar solution.

Accepted Answer

The answer of Oftentimes solubility of a compound limits the...

Question 19

Solution A has a concentration of 0.10 M sugar and Solution B has a concentration of 0.20 M sugar.If the two solutions are separated by a semipermeable membrane,which of the following occurs during osmosis?

Accepted Answer

The answer of Solution A has a concentration of 0.10...

Question 20

What is the final concentration of a solution prepared by diluting 35.0 mL of 12.0 M HCl to a final volume of 
?

Accepted Answer

When diluting a solution, the initial and final amounts of solute must be equal. We can use the formula:

M1V1 = M2V2

where M1 = 12.0 M (initial concentration), V1 = 35.0 mL (initial volume), M2 = unknown final concentration, and V2 = 11.0 mL (final volume).

Solving for M2, we get:

M2 = (M1V1)/V2 = (12.0 M x 35.0 mL)/11.0 mL = 38.18 M/mL

We need to convert this concentration to M, which means dividing by 1000 to convert from millimoles to moles and dividing by the final volume (11.0 mL) to get the concentration:

M2 = 38.18 M/mL / 1000 mL/L / 11.0 mL = 0.350 M

Therefore, the final concentration after dilution is 0.350 M, which corresponds to choice (D).

Quiz 13: Solutions

What will happen if a healthy red blood cell is placed into a container of pure water?

What is the concentration of sodium chloride in the final solution if 25.34 mL of 0.113 M BaCl₂ completely reacts and the total volume of the reaction is 110.4 mL,given the reaction: BaCl₂ (aq) + Na₂SO₄(aq) → BaSO₄ (s) + 2NaCl (aq)

What is the molality of a solution made by dissolving 14.7 g of C₆H₁₂O₆ into 150.0 mL of water? Assume the density of water is 1.00 g/mL.

What volume of 12.0 M HCl is required to make 75.0 mL of 3.50 M HCl?

How many grams of barium sulfate are produced if 25.34 mL of 0.113 M BaCl₂ completely react given the reaction: BaCl₂ (aq) + Na₂SO₄(aq) → BaSO₄ (s) + 2NaCl (aq)

What molarity should the stock solution be if you want to dilute 25.0 mL to 2.00 L and have the final concentration be 0.103 M?

How many milliliters of 0.755 M H₂SO₄ solution is needed to react with 55.0 mL of 2.50 M KOH solution? Given: 2 KOH (aq) + H₂SO₄ (aq) → 2 H₂O (l) + K₂SO₄ (aq)

What is the change in the freezing point of a solution made by dissolving 14.7 g of C₆H₁₂O₆ into 150.0 mL of water? The density of water is 1.00 g/mL and K_f = 1.86°C/m.

How many mL of 0.218 M sodium sulfate react with exactly 25.34 mL of 0.113 M BaCl₂ given the reaction: BaCl₂ (aq) + Na₂SO₄(aq) → BaSO₄ (s) + 2NaCl (aq)

Osmotic pressure is:

If you add 4.00 mL of pure water to 6.00 mL of 0.750 M NaCl solution,what is the concentration of sodium chloride in the diluted solution?

What is the change in the boiling point of a solution made by dissolving 14.7 g of C₆H₁₂O₆ into 150.0 mL of water? The density of water is 1.00 g/mL and K_b = 0.512°C/m.

Which of the following statements about colligative properties is FALSE?

Why is NOT a good idea to drink seawater when people are lost at sea?

In comparing a 0.25 molality aqueous NaCl solution to a 0.25 molality aqueous CaCl₂ solution,

What volume of 9.00 M nitric acid is needed to make 6.50 L of 1.25 M solution?

Oftentimes solubility of a compound limits the concentration of the solution that can be prepared.Use the solubility data given with each compound shown below to determine which compound would allow the preparation of a 10.0 Molar solution.

Solution A has a concentration of 0.10 M sugar and Solution B has a concentration of 0.20 M sugar.If the two solutions are separated by a semipermeable membrane,which of the following occurs during osmosis?

What is the final concentration of a solution prepared by diluting 35.0 mL of 12.0 M HCl to a final volume of ?

Quiz 13: Solutions

What will happen if a healthy red blood cell is placed into a container of pure water?

What is the concentration of sodium chloride in the final solution if 25.34 mL of 0.113 M BaCl2 completely reacts and the total volume of the reaction is 110.4 mL,given the reaction: BaCl2 (aq) + Na2SO4(aq) → BaSO4 (s) + 2NaCl (aq)

What is the molality of a solution made by dissolving 14.7 g of C6H12O6 into 150.0 mL of water? Assume the density of water is 1.00 g/mL.

What volume of 12.0 M HCl is required to make 75.0 mL of 3.50 M HCl?

How many grams of barium sulfate are produced if 25.34 mL of 0.113 M BaCl2 completely react given the reaction: BaCl2 (aq) + Na2SO4(aq) → BaSO4 (s) + 2NaCl (aq)

What molarity should the stock solution be if you want to dilute 25.0 mL to 2.00 L and have the final concentration be 0.103 M?

How many milliliters of 0.755 M H2SO4 solution is needed to react with 55.0 mL of 2.50 M KOH solution? Given: 2 KOH (aq) + H2SO4 (aq) → 2 H2O (l) + K2SO4 (aq)

What is the change in the freezing point of a solution made by dissolving 14.7 g of C6H12O6 into 150.0 mL of water? The density of water is 1.00 g/mL and Kf = 1.86°C/m.

How many mL of 0.218 M sodium sulfate react with exactly 25.34 mL of 0.113 M BaCl2 given the reaction: BaCl2 (aq) + Na2SO4(aq) → BaSO4 (s) + 2NaCl (aq)

Osmotic pressure is:

If you add 4.00 mL of pure water to 6.00 mL of 0.750 M NaCl solution,what is the concentration of sodium chloride in the diluted solution?

What is the change in the boiling point of a solution made by dissolving 14.7 g of C6H12O6 into 150.0 mL of water? The density of water is 1.00 g/mL and Kb = 0.512°C/m.

Which of the following statements about colligative properties is FALSE?

Why is NOT a good idea to drink seawater when people are lost at sea?

In comparing a 0.25 molality aqueous NaCl solution to a 0.25 molality aqueous CaCl2 solution,

What volume of 9.00 M nitric acid is needed to make 6.50 L of 1.25 M solution?

Oftentimes solubility of a compound limits the concentration of the solution that can be prepared.Use the solubility data given with each compound shown below to determine which compound would allow the preparation of a 10.0 Molar solution.

Solution A has a concentration of 0.10 M sugar and Solution B has a concentration of 0.20 M sugar.If the two solutions are separated by a semipermeable membrane,which of the following occurs during osmosis?

What is the final concentration of a solution prepared by diluting 35.0 mL of 12.0 M HCl to a final volume of ?

What is the concentration of sodium chloride in the final solution if 25.34 mL of 0.113 M BaCl₂ completely reacts and the total volume of the reaction is 110.4 mL,given the reaction: BaCl₂ (aq) + Na₂SO₄(aq) → BaSO₄ (s) + 2NaCl (aq)

What is the molality of a solution made by dissolving 14.7 g of C₆H₁₂O₆ into 150.0 mL of water? Assume the density of water is 1.00 g/mL.

How many grams of barium sulfate are produced if 25.34 mL of 0.113 M BaCl₂ completely react given the reaction: BaCl₂ (aq) + Na₂SO₄(aq) → BaSO₄ (s) + 2NaCl (aq)

How many milliliters of 0.755 M H₂SO₄ solution is needed to react with 55.0 mL of 2.50 M KOH solution? Given: 2 KOH (aq) + H₂SO₄ (aq) → 2 H₂O (l) + K₂SO₄ (aq)

What is the change in the freezing point of a solution made by dissolving 14.7 g of C₆H₁₂O₆ into 150.0 mL of water? The density of water is 1.00 g/mL and K_f = 1.86°C/m.

How many mL of 0.218 M sodium sulfate react with exactly 25.34 mL of 0.113 M BaCl₂ given the reaction: BaCl₂ (aq) + Na₂SO₄(aq) → BaSO₄ (s) + 2NaCl (aq)

What is the change in the boiling point of a solution made by dissolving 14.7 g of C₆H₁₂O₆ into 150.0 mL of water? The density of water is 1.00 g/mL and K_b = 0.512°C/m.

In comparing a 0.25 molality aqueous NaCl solution to a 0.25 molality aqueous CaCl₂ solution,