Given the table of specific heat values below,what is the identity of a 26.2 g metal sample that increases by 8.5°C when 100.0 J of energy is absorbed?

Question

Quizplus · Accepted Answer

Using the formula Q = mCΔT, where Q is the amount of energy absorbed, m is the mass of the metal, C is the specific heat, and ΔT is the change in temperature, we can calculate the specific heat of the metal sample:

C = Q / (mΔT) = 100 J / (26.2 g × 8.5 °C) = 0.456 J/g°C

Comparing this value to the specific heat values in the table, we see that the closest match is iron (Fe) with a specific heat of 0.449 J/g°C. Therefore, the identity of the metal sample is likely Fe.

Given the Table of Specific Heat Values Below,what Is the Identity