Consider the minimumPosition method from the SelectionSorter class. Complete the code to write a maximumPosition method that returns the index of the largest element in the range from index from to the end of the array.
Private static int minimumPosition(int[] a, int from)
{
Int minPos = from;
For (int i = from + 1; i < a.length; i++)
{
If (a[i] < a[minPos]) { minPos = i; }
}
Return minPos;
}
Private static int maximumPosition(int[] a, int from)
{
Int maxPos = from;
For (int i = from + 1; i < a.length; i++)
{
________________
}
Return maxPos;
}
A) if(a[i] > a[maxPos]) { maxPos = i; }
B) if(a[i] == a[maxPos]) { maxPos = i; }
C) if(a[i] < a[maxPos]) { maxPos = i; }
D) if(a[i] <= a[maxPos]) { maxPos = i; }
Correct Answer:
Verified
Q5: In each iteration, selection sort places which
Q6: Consider the sort method for selection sort
Q9: Consider the swap method shown below from
Q13: After 5 iterations of selection sort working
Q14: The performance of an algorithm is most
Q15: Suppose you wanted to test your sort
Q16: What type of algorithm places elements in
Q19: Which selection sort iteration guarantees the array
Q27: How large does n need to be
Q33: What is the smallest value of n
Unlock this Answer For Free Now!
View this answer and more for free by performing one of the following actions
Scan the QR code to install the App and get 2 free unlocks
Unlock quizzes for free by uploading documents