A concentration cell consists of two Zn/Zn²⁺ electrodes. The electrolyte in compartment A is 0.10 M Zn(NO₃)₂and in compartment B is 0.60 M Zn(NO₃)₂. What is the voltage of the cell at 25°C?

Question

Quizplus · Accepted Answer

The voltage of a concentration cell can be determined using the Nernst equation:

Ecell = (RT/nF) * ln(Q)

where R is the gas constant (8.314 J/mol-K), T is the temperature in Kelvin (298 K), n is the number of electrons transferred (in this case 2), F is Faraday's constant (96,485 C/mol), and Q is the reaction quotient. For a concentration cell, Q is given by:

Q = [Zn2+ (high conc.)]/[Zn2+ (low conc.)]

Substituting the values given in the problem, we get:

Q = [Zn2+ (0.60 M)]/[Zn2+ (0.10 M)] = 6

Plugging in all the values, we get:

Ecell = (0.0257 V) * ln(6)

Ecell = 0.023 V

Therefore, the answer is C.

A Concentration Cell Consists of Two Zn/Zn2+ Electrodes

A Concentration Cell Consists of Two Zn/Zn²⁺ Electrodes