Arrange the following bonds in decreasing order of ionic character, putting the most ionic first. $$\begin{array} { c c c c }
\text { C-C } & \text { C-N } & \text { C-O } & \text { Na-O } \
\text { I } & \text { II } & \text { III } & \text { IV }
\end{array}$$

Question

Arrange the following bonds in decreasing order of ionic character, putting the most ionic first. $$\begin{array} { c c c c } 
\text { C-C } & \text { C-N } & \text { C-O } & \text { Na-O } \
\text { I } & \text { II } & \text { III } & \text { IV }
\end{array}$$

Quizplus · Accepted Answer

The ionic character of a bond is determined by the difference in electronegativity between the two atoms. Na-O has the highest difference, making it the most ionic, followed by C-O, C-N, and C-C, which is the least ionic.

Arrange the Following Bonds in Decreasing Order of Ionic Character