A steel ball is thrown in the air with a speed of 3.6 m/s at an angle of 70° from the horizontal.It drops on another steel ball of 1.4 times its mass resting on a sandy surface.If the original ball comes to a rest after the collision and the resting ball bounces,find the horizontal component of its velocity.

Question

Quizplus · Accepted Answer

The horizontal component of the velocity of the first ball is 3.6 * cos(70°). Using conservation of momentum, the horizontal component of the velocity of the second ball is (3.6 * cos(70°)) / 1.4, which is approximately 0.88 m/s.

A Steel Ball Is Thrown in the Air with a Speed