A 0.24 kg blob of clay is thrown at a wall with an initial velocity of 23 m/s.If the clay comes to a stop in 91 ms,what is the average force experienced by the clay?

Question

Quizplus · Accepted Answer

The average force experienced by the clay is equal to the change in momentum divided by the time interval. The change in momentum is equal to the final momentum minus the initial momentum. The final momentum is zero, since the clay comes to a stop. The initial momentum is equal to the mass of the clay times the initial velocity. Therefore, the change in momentum is equal to -0.24 kg * 23 m/s = -5.52 kg*m/s. The time interval is equal to 91 ms = 0.091 s. Therefore, the average force experienced by the clay is equal to -5.52 kg*m/s / 0.091 s = 61 N.

A 024 Kg Blob of Clay Is Thrown at a Wall