A 23 kg mass is connected to a nail on a frictionless table by a (massless)string of length 1.3 m.If the tension in the string is 51 N while the mass moves in a uniform circle on the table,how long does it take for the mass to make one complete revolution?
A)4.8 s
B)3.8 s
C)4.5 s
D)5.2 s

Question

Quizplus · Accepted Answer

The tension in the string provides the centripetal force required for circular motion. Using the formula for centripetal force, $ F = \frac{mv^2}{r} $, where $ m = 23 \, \text{kg} $, $ r = 1.3 \, \text{m} $, and $ F = 51 \, \text{N} $, we can solve for $ v $. Then, using $ v = \frac{2\pi r}{T} $, solve for $ T $, the period of revolution. The correct calculation gives $ T \approx 4.8 \, \text{s} $.

A 23 Kg Mass Is Connected to a Nail on a Frictionless