An aerobatic aircraft is to perform a spiral maneuver.If the engine provides a tangential acceleration of 5.41 m/s²,what is the radial acceleration it will experience at the end of a circle 30.8 m in radius,if the speed at the beginning of the stunt was 55.0 m/s? A)166 m/s² B)132 m/s² C)98 m/s² D)257 m/s²

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Quizplus · Accepted Answer

The radial (centripetal) acceleration is calculated using the formula a_r = v^2 / r. At the end of the circle, the speed v can be found using v = v_0 + at, where v_0 is the initial speed, a is the tangential acceleration, and t is the time. However, since the problem asks for the radial acceleration at the end of the circle, we use the initial speed for calculation: a_r = (55.0 m/s)^2 / 30.8 m = 166 m/s^2.

An Aerobatic Aircraft Is to Perform a Spiral Maneuver