A 1.90 × 10¹⁴ Hz electromagnetic wave propagates in carbon tetrachloride with a speed of 2.05 × 10⁸ m/s.The wavelength of the wave in vacuum is closest to: A)1580 nm B)1080 nm C)1260 nm D)1420 nm E)1740 nm

Question

Quizplus · Accepted Answer

The wavelength of an electromagnetic wave is given by the speed of light divided by the frequency. In vacuum, the speed of light is 3.00 × 10^8 m/s. The frequency of the wave is 1.90 × 10^14 Hz. Therefore, the wavelength of the wave in vacuum is:λ = c/f = (3.00 × 10^8 m/s)/(1.90 × 10^14 Hz) = 1580 nmTherefore, the correct answer is A.

A 190 × 1014 Hz Electromagnetic Wave Propagates in Carbon Tetrachloride

A 190 × 10¹⁴ Hz Electromagnetic Wave Propagates in Carbon Tetrachloride