A transmitter is operating at an average of 4.00 kW of power.What is the average intensity of the signal 8.00 km from the transmitter? A)4.97 μW/m² B)2.49 μW/m² C)0.00497 W/m² D)0.00249 W/m²

Question

Quizplus · Accepted Answer

The average intensity of the signal is given by the equation:$$I = \frac{P}{4\pi r^2}$$where:* I is the intensity in W/m^2* P is the power in W* r is the distance from the transmitter in mPlugging in the given values, we get:$$I = \frac{4.00 	imes 10^3 	ext{ W}}{4\pi (8.00 	imes 10^3 	ext{ m})^2} = 4.97 	imes 10^{-6} 	ext{ W/m}^2$$Converting to μW/m^2, we get:$$I = 4.97 	imes 10^{-6} 	ext{ W/m}^2 	imes \frac{10^6 \mu	ext{W}}{1 	ext{ W}} = 4.97 \mu	ext{W/m}^2$$Therefore, the average intensity of the signal 8.00 km from the transmitter is 4.97 μW/m^2.

A Transmitter Is Operating at an Average of 4