A 2.0 m conductor is formed into a square and placed in the horizontal xy-plane.A magnetic field is oriented 30.0º above the horizontal with a strength of 9.0 T.What is the magnetic flux through the conductor? A)1.1 T ∙ m² B)1.9 T ∙ m² C)2.3 T ∙ m² D)18 T ∙ m²

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Quizplus · Accepted Answer

The magnetic flux through the conductor is given by the product of the magnetic field strength, the area of the conductor, and the cosine of the angle between the magnetic field and the normal to the conductor. In this case, the area of the conductor is 2.0 m x 2.0 m = 4.0 m^2, and the cosine of the angle between the magnetic field and the normal to the conductor is cos(30.0º) = 0.866. Therefore, the magnetic flux through the conductor is:$$\Phi = B A \cos	heta = (9.0 	ext{ T})(4.0 	ext{ m}^2)(0.866) = 31.9 	ext{ T} \cdot 	ext{m}^2$$

A 20 M Conductor Is Formed into a Square and Placed