A closed-loop conductor with radius 2.0 m is located in a changing magnetic field.If the maximum emf induced in the loop is 2.0 V,what is the maximum rate at which the magnetic field strength is changing if the magnetic field is oriented perpendicular to the plane in which the loop lies?
A)0.16 T/s
B)1.0 T/s
C)0.080 T/s
D)2.0 T/s

Question

Quizplus · Accepted Answer

The maximum emf (ε) induced in a loop is given by Faraday's law: ε = dΦ/dt, where Φ is the magnetic flux. For a circular loop, Φ = B * A = B * π * r^2. Given ε = 2.0 V, r = 2.0 m, and A = π * (2.0)^2, we solve for dB/dt: 2.0 = π * (2.0)^2 * dB/dt, giving dB/dt = 0.16 T/s.

A Closed-Loop Conductor with Radius 2