A proton with speed 1.5 × 105 m/s falls through a potential difference of 100 volts,gaining speed.What is the speed reached?
A) 4.56 × 105 m/s
B) 2.04 × 105 m/s
C) 3.55 × 105 m/s
D) 8.80 × 105 m/s
E) 1.55 × 106 m/s
Correct Answer:
Verified
Q1: A 1.0 μF capacitor has a potential
Q2: Two parallel plates are separated by 1.0
Q4: Two parallel circular plates with radius 7.0
Q5: A 6.0 μC negative charge is attracted
Q6: Two parallel plates that are initially uncharged
Q7: A charge of 3.0 μC and
Q8: Consider the group of charges in this
Q9: A 3.0 pF capacitor consists of two
Q10: A sphere with radius 2.0 mm
Q11: A 100.0 pF capacitor consists of
Unlock this Answer For Free Now!
View this answer and more for free by performing one of the following actions
Scan the QR code to install the App and get 2 free unlocks
Unlock quizzes for free by uploading documents