A 100.0 pF capacitor consists of two circular plates of radius 0.40 mm.How far apart are the plates? (The value of εo is 8.85 $\times$ 10 -12 C²/N·m². )

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The capacitance of a parallel-plate capacitor is given by:$$C = \frac{\epsilon_0 A}{d}$$where:* C is the capacitance in farads (F)* $\epsilon_0$ is the permittivity of free space (8.85 x 10^-12 C^2/N·m^2)* A is the area of the plates in square meters (m^2)* d is the distance between the plates in meters (m)We are given the following information:* C = 100.0 pF = 100.0 x 10^-12 F* r = 0.40 mm = 0.40 x 10^-3 m* $\epsilon_0$ = 8.85 x 10^-12 C^2/N·m^2We can use the formula above to solve for d:$$d = \frac{\epsilon_0 A}{C}$$$$d = \frac{(8.85 x 10^-12 C^2/N·m^2)(\pi (0.40 x 10^-3 m)^2)}{100.0 x 10^-12 F}$$$$d = 0.044 \mu m$$Therefore, the correct answer is A) 0.044 μm.

A 1000 PF Capacitor Consists of Two Circular Plates of Radius