A 3.0 μC point charge and a 9.0 μC point charge are initially infinitely far apart.How much work does it take to bring the 3.0 μC point charge to x = 3.0 mm,y = 0.0 mm,and the 9.0 μC point charge to x = -3.0 mm,y = 0.0 mm? (The value of k is 9.0 $\times$ 10⁹ N·m²/C². )

Question

Quizplus · Accepted Answer

The work done in bringing the charges from infinity to the given positions is given by:$$W = k\frac{q_1q_2}{r_{12}}$$where k is Coulomb's constant, q1 and q2 are the charges, and r12 is the distance between the charges.In this case, q1 = 3.0 μC, q2 = 9.0 μC, and r12 = 6.0 mm = 0.006 m.Substituting these values into the equation, we get:$$W = (9.0 	imes 10^9 	ext{ N$\cdot$m}^2/	ext{C}^2)\frac{(3.0 	imes 10^{-6} 	ext{ C})(9.0 	imes 10^{-6} 	ext{ C})}{0.006 	ext{ m}}$$$$W = 41 	ext{ J}$$Therefore, the work done in bringing the charges from infinity to the given positions is 41 J.

A 30 μC Point Charge and a 9 ×\times× 109 N·m2/C2

A 30 μC Point Charge and a 9 $\times$ 10⁹ N·m²/C²