A parallel-plate capacitor consists of two parallel,square plates that have dimensions 1.0 cm by 1.0 cm.If the plates are separated by 1.0 mm,and the space between them is filled with teflon,what is the capacitance? (The dielectric constant for teflon is 2.1. )

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Quizplus · Accepted Answer

The capacitance of a parallel-plate capacitor is given by C = (ε₀ * κ * A) / d, where ε₀ is the permittivity of free space (8.85 x 10⁻¹² F/m), κ is the dielectric constant, A is the area of the plates, and d is the separation between the plates. Substituting the given values, C = (8.85 x 10⁻¹² F/m * 2.1 * 1.0 x 10⁻⁴ m²) / 1.0 x 10⁻³ m = 1.9 x 10⁻¹² F = 1.9 pF.

A Parallel-Plate Capacitor Consists of Two Parallel,square Plates That Have