An object undergoing simple harmonic motion has a maximum displacement of 6.2 m at t = 0.0 s.If the angular frequency of oscillation is 1.6 rad/s,what is the object's displacement when t = 3.5 s?
A)4.8 m
B)5.6 m
C)3.7 m
D)3.1 m

Question

Quizplus · Accepted Answer

The displacement of the object undergoing simple harmonic motion can be given by the equation:
x = A*cos(ωt)
where A is the amplitude, ω is the angular frequency and t is the time.
Given that A = 6.2m and ω = 1.6 rad/s
So, when t = 3.5s 
x = A*cos(ωt) = 6.2*cos(1.6*3.5) = 4.8 m (approx) 
Therefore, the best choice is A) 4.8 m.

An Object Undergoing Simple Harmonic Motion Has a Maximum Displacement