A 0.25 kg harmonic oscillator has a total oscillation energy of 4.0 J.If the oscillation amplitude is 20.0 cm,what is the oscillation frequency?
A)4.5 Hz
B)1.4 Hz
C)2.3 Hz
D)3.1 Hz

Question

Quizplus · Accepted Answer

The oscillation frequency is given by:$$f = \sqrt{\frac{k}{m}}$$where k is the spring constant and m is the mass. The spring constant is given by:$$k = \frac{4.0 J}{(0.20 m)^2} = 100 N/m$$Therefore, the oscillation frequency is:$$f = \sqrt{\frac{100 N/m}{0.25 kg}} = 4.5 Hz$$

A 025 Kg Harmonic Oscillator Has a Total Oscillation Energy of of 4.0