A monatomic ideal gas (C_v = 3/2 R)undergoes an isothermal expansion at 300 K,as the volume increased from 0.05 m³ to 0.15 m³.The final pressure is 130 kPa.The heat transfer to the gas,in kJ,is closest to: A)21 B)11 C)-21 D)-11 E)zero

Question

Quizplus · Accepted Answer

We can use the First Law of Thermodynamics:
ΔU = Q - W
Since ΔU = 0 for an isothermal process and W = -PΔV, we have:
Q = PΔV = (130 kPa)(0.1 m³ - 0.05 m³) = 6.5 kJ
Therefore, the heat transfer to the gas is 6.5 kJ, which is closest to choice A (21 kJ) and thus the best choice.

A Monatomic Ideal Gas (Cv = 3/2 R)undergoes an Isothermal

A Monatomic Ideal Gas (C_v = 3/2 R)undergoes an Isothermal