The figure shows 0.0074 mol of gas that undergoes the process 1 → 2 → 3.What is the volume V₃? A)740 cm³ B)630 cm³ C)510 cm³ D)400 cm³

Question

Quizplus · Accepted Answer

We can use the ideal gas law to solve for the volume:

PV = nRT

At point 1, we know the number of moles (0.0074 mol) and the temperature is constant, so we can simplify the equation to:

P1V1 = nRT

At point 2, we know the pressure and the volume, so we can solve for the new number of moles:

n2 = (P2V2)/(RT)

At point 3, we know the pressure and the new number of moles, so we can solve for the new volume:

P3V3 = n2RT

Putting it all together:

V3 = (P2V2/P1) * (nRT/P3) = (1/4) * (0.0074 mol * 0.0821 L atm mol^-1 K^-1 * 300 K / 0.5 atm)

V3 = 0.740 L = 740 cm3

The Figure Shows 0