A 24.0 kg sample of ice is at 0.00°C.How much heat is needed to melt it? (For water Lf = 334 kJ/kg and Lv = 2257 kJ/kg. ) A)8.02 × 10³ kJ B)2.19 × 10⁶ kJ C)0.00 kJ D)5.42 × 10⁴ kJ

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Quizplus · Accepted Answer

The heat needed to melt the ice is calculated using the formula Q = m * Lf, where m is the mass and Lf is the latent heat of fusion. For a 24.0 kg sample, Q = 24.0 kg * 334 kJ/kg = 8016 kJ, which is approximately 8.02 × 10^3 kJ.

A 240 Kg Sample of Ice Is at 0